General Chemistry (Part 5)
(1st Partnership Task)
For all level XII students: Choose one problem and answer it by submitting your identity and answer in comment bar. The last submit is September 6, 2010. Your score will be displayed on laboratory wall paper. When a problem has been answered, you must choose another one and submit your second answer for once again. The first answer will not be checked.
Thank you!
1. Flame color of alkaline
Lithium :
Sodium :
Potassium :
Rubidium :
Cesium :

2. Which one is the highest atomic radii?
3. Which one is the largest ionization energy?
4. Which one is the strongest base?
5. Which one does not react with water? Explain your reason for this fact.
6. Write general chemical equation between alkaline with water!
7. a) State general chemical equation between alkaline with hydrogen gas
b) State a reaction between Na with excess oxygen.
What is oxidation number of O in this reaction?
c) State a reaction between Na with limited oxygen.
What is oxidation number of O in this reaction?
d) What are products produced by a reaction between K/Rb/Cs with excess oxygen?
What is oxidation number of O in this reaction?
7. Explain how to prove that alkaline metals are quite reactive!

45 Comments:
Name : R.M. Andriyan & Tito Faradhimu
Class : XII PSIA 1
1. Flame color of alkaline
Lithium : Red (Crimson)
Sodium : Yellow (Intense)
Potassium : Violet (Pale)
Rubidium : Violet (Pale)
Cesium : Violet (Pale)
Name: Natasia & Nurul Putri Atika
Class: XII PSIA 1
2) Francium has the highest atomic radii in group I, but if we want to choose from the list given in problem number 1, Cesium is the one that has the highest atomic radii.
Name : Mertiana Puspasari & Syarifatul Adlah
Class: XII PSIA 5
3)The largest ionization energy is Li,because the ionization energy is large, that means it takes a lot of energy to remove the outermost electron.And it uses the smallest number of energy levels.
Name : Aisyah Fatriani & Melinda Dwi A
Class : XII PSIA 5
7.1) Appropriate reactivity thank the metal loses electrons depends on its simplicity so that it reflects the nature of the ionization energy. Alkali metals have relatively low ionization energy from top to bottom and lower. So, in summary appropriate reactivity thank alkali metal increases from top to bottom.
Name : Ira Meliani & Masayu Sarah Nafisah
class : XII PSIA 1
6. 2L (s) + 2H2O(l) → 2LOH (aq) + H2(g)
L = Alkaline Metal
Name : Cindy Febrina and Dina Widya HN
Class: XII PSIA 1
5. All of alkali unsure except H can react with water to form base and hydrogen gas. Li can react with water but slowly, then Na can react very well with water. Rubidium, caesium and potassium are very explosive with water.
Name : Aresta Agustarini and M. Ridho R.
Class: XII PSIA 1
Problem
7.b) State a reaction between Na with excess oxygen. What is oxidation number of O in this reaction?
Answer:
If it reacts with excess oxygen, Na will produce peroxide.
2Na (s) + O2 (g) ---> Na2O2 (s)
And the oxidation number in this reaction is -1.
Name : Madania and Dita Dwimayasari
Class : XII PSIA 1
4. all of in group I is the strongest base, they are Li, Na, K, Rb, Cs, Fr. example : LiOH, KOH, RbOH, CsOH, NaOH, etc.
Name : Aresta Agustarini and M. Ridho R.
Class: XII PSIA 1
Problem
7.b) State a reaction between Na with excess oxygen. What is oxidation number of O in this reaction?
Answer:
If it reacts with excess oxygen, Na will produce peroxide.
2Na (s) + O2 (g) ---> Na2O2 (s)
And the oxidation number in this reaction is -1.
This comment has been removed by the author.
This comment has been removed by the author.
This comment has been removed by the author.
Name: Ahmad Doni Meidianto & Santrio Basri
XII PSIA 5
2. Cesium has the highest atomic radii from the list above.
Thanks
Name : Aresta Agustarini and Indah Marizka
Class: XII PSIA 1
Problem
7.b) State a reaction between Na with excess oxygen. What is oxidation number of O in this reaction?
Answer:
If it reacts with excess oxygen, Na will produce peroxide.
2Na (s) + O2 (g) ---> Na2O2 (s)
And the oxidation number in this reaction is -1.
Name : Andri B. W. and M. Ridho Rifhansyah
Class: XII PSIA 1
7. a State general chemical equation between alkaline with hydrogen gas
Answer:
It it is heated, alkali metal can react with hydrogen produce hydride. (an ion compound which its hydrogen has oxidation number -1)
2L (s) + H2 (g) --> 2LH (s)
Name : Yulya Aryani
Class : XII PSIA 2
1. Flame color of alkaline
Lithium : Red
Sodium : Yellow
Potassium : Violet
Rubidium : Violet
Cesium : Violet
Name : Dyer Patriocta & Muhammad Fajriandi
Class : XII PSIA 5.
6.1. 2L(s)+H2(g) -> 2LH(s).
6.2. 2L(s)+O2(g) -> L2O2(s) (oxydation number = -1).
6.3. 4L(s)+O2(g) -> 2L2O(s) (oxydation number = -2).
6.4. It will products superoksida. (oxydation number = -1/2).
Name : Indah Fitri Nurdianthi
Class : XII PSIA 2
2. Cesium (from the list in number 1).
Name : Indah Fitri Nurdianthi
Class : XII PSIA 2
2. Cesium (from list in number 1).
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is : 2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1), losing one electron per Na atom,
O decreases, each from (0) to (-1).
so,the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class :
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Indah Fitri Nurdianthi
Class : XII PSIA 2
2.Cesium (from the list in number 1)
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.
7.c
Name: Bagus Cahya & Bondan Try Hoetomo
Class: XII PSIA 3
if Na reacts with limited amount of O2, O2 will produce peroxide
2Na(s)+1/2O2(g) -> Na2O(s)
or
4Na(s)+O2 -> 2Na2O
the oxidation number is -1
7c. name: bagus indra cahya & bondan try hoetomo
class: xii psia 3
Na(s)+1/2O2(g) --> Na2O(s)
Na will produce oxide
the oxidation number in this reaction is
Na=+1, O= -2
Name :P Dwi Juwanita Putri & Khoiriyah Sari
Class : XII PSIA 5
No.7
Flame color of alkaline earth metals
Be : Colorless
Mg : Colorless
Ca : Brick-red
Sr : Red
Ba : Green
Because of their flames colors, both alkaline metals alkaline earth metals will be used as give color to the fireworks.
Name :P Dwi Juwanita Putri & Khoiriyah Sari
Class : XII PSIA 5
No.7
Flame color of alkaline earth metals
Be : Colorless
Mg : Colorless
Ca : Brick-red
Sr : Red
Ba : Green
Because of their flames colors, both alkaline metals alkaline earth metals will be used as give color to the fireworks.
Name : Maulia Wisda E.C & R A Delila Tsaniyah
class : XII PSIA 2
6. 2L(s) + 2H2O(l) → 2LOH(aq) + H2(g)
L = Alkaline Metal
Name : Premia Utianty & Rizka Amalia Hasanah
class: XII.IPA.3
1.Lithium : Red
Sodium : yellow ( gold )
potassium : violet
Rubidium : red
cesium : Blue
Name : A. Dodi M
class: XII PSIA 3
6. 2L(s) + 2H2O(l) → 2LOH(aq) + H2(g)
L = Alkaline Metal
Name : rizka intan y and yustia tafarani
Class : XII PSIA 4
4. all of in group I is the strongest base, they are Li, Na, K, Rb, Cs, Fr.
example :
LiOH,
KOH,
RbOH,
CsOH,
NaOH, etc.
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