September 19, 2011

General Chemistry (Part 5)

CHEMISTRY OF GROUP 1
(1st Partnership Task)

For all level XII students: Choose one problem and answer it by submitting your identity and answer in comment bar. The last submit is September 6, 2010. Your score will be displayed on laboratory wall paper. When a problem has been answered, you must choose another one and submit your second answer for once again. The first answer will not be checked.
Thank you!


1. Flame color of alkaline
Lithium :
Sodium :
Potassium :
Rubidium :
Cesium :


2. Which one is the highest atomic radii?
3. Which one is the largest ionization energy?
4. Which one is the strongest base?
5. Which one does not react with water? Explain your reason for this fact.
6. Write general chemical equation between alkaline with water!
7. a) State general chemical equation between alkaline with hydrogen gas
b) State a reaction between Na with excess oxygen.
What is oxidation number of O in this reaction?
c) State a reaction between Na with limited oxygen.
What is oxidation number of O in this reaction?
d) What are products produced by a reaction between K/Rb/Cs with excess oxygen?
What is oxidation number of O in this reaction?
7. Explain how to prove that alkaline metals are quite reactive!

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45 Comments:

Blogger berly RS said...

Name : R.M. Andriyan & Tito Faradhimu
Class : XII PSIA 1

1. Flame color of alkaline
Lithium : Red (Crimson)
Sodium : Yellow (Intense)
Potassium : Violet (Pale)
Rubidium : Violet (Pale)
Cesium : Violet (Pale)

August 27, 2010  
Anonymous Anonymous said...

Name: Natasia & Nurul Putri Atika
Class: XII PSIA 1

2) Francium has the highest atomic radii in group I, but if we want to choose from the list given in problem number 1, Cesium is the one that has the highest atomic radii.

August 27, 2010  
Blogger mertiana puspasari said...

Name : Mertiana Puspasari & Syarifatul Adlah
Class: XII PSIA 5

3)The largest ionization energy is Li,because the ionization energy is large, that means it takes a lot of energy to remove the outermost electron.And it uses the smallest number of energy levels.

August 29, 2010  
Anonymous Anonymous said...

Name : Aisyah Fatriani & Melinda Dwi A
Class : XII PSIA 5

7.1) Appropriate reactivity thank the metal loses electrons depends on its simplicity so that it reflects the nature of the ionization energy. Alkali metals have relatively low ionization energy from top to bottom and lower. So, in summary appropriate reactivity thank alkali metal increases from top to bottom.

August 29, 2010  
Anonymous Anonymous said...

Name : Ira Meliani & Masayu Sarah Nafisah
class : XII PSIA 1

6. 2L (s) + 2H2O(l) → 2LOH (aq) + H2(g)

L = Alkaline Metal

August 30, 2010  
Anonymous Anonymous said...

Name : Cindy Febrina and Dina Widya HN
Class: XII PSIA 1

5. All of alkali unsure except H can react with water to form base and hydrogen gas. Li can react with water but slowly, then Na can react very well with water. Rubidium, caesium and potassium are very explosive with water.

August 30, 2010  
Blogger Ridho Rifhansyah said...

Name : Aresta Agustarini and M. Ridho R.
Class: XII PSIA 1

Problem
7.b) State a reaction between Na with excess oxygen. What is oxidation number of O in this reaction?

Answer:
If it reacts with excess oxygen, Na will produce peroxide.

2Na (s) + O2 (g) ---> Na2O2 (s)

And the oxidation number in this reaction is -1.

August 30, 2010  
Anonymous Anonymous said...

Name : Madania and Dita Dwimayasari
Class : XII PSIA 1

4. all of in group I is the strongest base, they are Li, Na, K, Rb, Cs, Fr. example : LiOH, KOH, RbOH, CsOH, NaOH, etc.

August 30, 2010  
Anonymous Anonymous said...

Name : Aresta Agustarini and M. Ridho R.
Class: XII PSIA 1

Problem
7.b) State a reaction between Na with excess oxygen. What is oxidation number of O in this reaction?

Answer:
If it reacts with excess oxygen, Na will produce peroxide.

2Na (s) + O2 (g) ---> Na2O2 (s)

And the oxidation number in this reaction is -1.

August 30, 2010  
Blogger Ridho Rifhansyah said...

This comment has been removed by the author.

August 30, 2010  
Blogger Ridho Rifhansyah said...

This comment has been removed by the author.

August 30, 2010  
Blogger Ridho Rifhansyah said...

This comment has been removed by the author.

August 30, 2010  
Blogger Ahmad Doni Meidianto said...

Name: Ahmad Doni Meidianto & Santrio Basri
XII PSIA 5

2. Cesium has the highest atomic radii from the list above.

Thanks

August 30, 2010  
Anonymous Anonymous said...

Name : Aresta Agustarini and Indah Marizka
Class: XII PSIA 1

Problem
7.b) State a reaction between Na with excess oxygen. What is oxidation number of O in this reaction?

Answer:
If it reacts with excess oxygen, Na will produce peroxide.

2Na (s) + O2 (g) ---> Na2O2 (s)

And the oxidation number in this reaction is -1.

August 31, 2010  
Blogger Ridho Rifhansyah said...

Name : Andri B. W. and M. Ridho Rifhansyah
Class: XII PSIA 1

7. a State general chemical equation between alkaline with hydrogen gas

Answer:
It it is heated, alkali metal can react with hydrogen produce hydride. (an ion compound which its hydrogen has oxidation number -1)

2L (s) + H2 (g) --> 2LH (s)

August 31, 2010  
Anonymous Anonymous said...

Name : Yulya Aryani
Class : XII PSIA 2

1. Flame color of alkaline
Lithium : Red
Sodium : Yellow
Potassium : Violet
Rubidium : Violet
Cesium : Violet

August 31, 2010  
Anonymous Anonymous said...

Name : Dyer Patriocta & Muhammad Fajriandi
Class : XII PSIA 5.

6.1. 2L(s)+H2(g) -> 2LH(s).
6.2. 2L(s)+O2(g) -> L2O2(s) (oxydation number = -1).
6.3. 4L(s)+O2(g) -> 2L2O(s) (oxydation number = -2).
6.4. It will products superoksida. (oxydation number = -1/2).

September 01, 2010  
Anonymous Anonymous said...

Name : Indah Fitri Nurdianthi
Class : XII PSIA 2

2. Cesium (from the list in number 1).

September 01, 2010  
Blogger Indah Fitri said...

Name : Indah Fitri Nurdianthi
Class : XII PSIA 2

2. Cesium (from list in number 1).

September 01, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2

7.) a reaction between Na with excess oxygen is : 2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1), losing one electron per Na atom,
O decreases, each from (0) to (-1).
so,the oxidation number of O in this reaction is -1.

September 02, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class :

September 02, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2

7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 02, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2

7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 02, 2010  
Anonymous Anonymous said...

Name : Indah Fitri Nurdianthi
Class : XII PSIA 2

2.Cesium (from the list in number 1)

September 02, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Blogger veranika_santiani said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Blogger veranika_santiani said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Blogger veranika_santiani said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Blogger veranika_santiani said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Blogger veranika_santiani said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

Name : Veranika Santiani Fani
Class : XII PSIA 2
7.) a reaction between Na with excess oxygen is :
2Na(s) + O2(s) ==> Na2O2(s)
Na increases, each from (0) to (+1)
O decreases, each from (0) to (-1)
So, the oxidation number of O in this reaction is -1.

September 05, 2010  
Anonymous Anonymous said...

7.c
Name: Bagus Cahya & Bondan Try Hoetomo
Class: XII PSIA 3

if Na reacts with limited amount of O2, O2 will produce peroxide
2Na(s)+1/2O2(g) -> Na2O(s)
or
4Na(s)+O2 -> 2Na2O

the oxidation number is -1

September 06, 2010  
Anonymous Anonymous said...

7c. name: bagus indra cahya & bondan try hoetomo
class: xii psia 3

Na(s)+1/2O2(g) --> Na2O(s)
Na will produce oxide

the oxidation number in this reaction is
Na=+1, O= -2

September 06, 2010  
Anonymous Anonymous said...

Name :P Dwi Juwanita Putri & Khoiriyah Sari
Class : XII PSIA 5

No.7
Flame color of alkaline earth metals
Be : Colorless
Mg : Colorless
Ca : Brick-red
Sr : Red
Ba : Green
Because of their flames colors, both alkaline metals alkaline earth metals will be used as give color to the fireworks.

September 14, 2010  
Anonymous Anonymous said...

Name :P Dwi Juwanita Putri & Khoiriyah Sari
Class : XII PSIA 5

No.7
Flame color of alkaline earth metals
Be : Colorless
Mg : Colorless
Ca : Brick-red
Sr : Red
Ba : Green
Because of their flames colors, both alkaline metals alkaline earth metals will be used as give color to the fireworks.

September 14, 2010  
Blogger MWEC .ewis said...

Name : Maulia Wisda E.C & R A Delila Tsaniyah
class : XII PSIA 2

6. 2L(s) + 2H2O(l) → 2LOH(aq) + H2(g)

L = Alkaline Metal

September 15, 2010  
Anonymous Anonymous said...

Name : Premia Utianty & Rizka Amalia Hasanah
class: XII.IPA.3

1.Lithium : Red
Sodium : yellow ( gold )
potassium : violet
Rubidium : red
cesium : Blue

September 15, 2010  
Anonymous Anonymous said...

Name : A. Dodi M
class: XII PSIA 3

6. 2L(s) + 2H2O(l) → 2LOH(aq) + H2(g)

L = Alkaline Metal

September 17, 2010  
Anonymous Anonymous said...

Name : rizka intan y and yustia tafarani
Class : XII PSIA 4

4. all of in group I is the strongest base, they are Li, Na, K, Rb, Cs, Fr.
example :
LiOH,
KOH,
RbOH,
CsOH,
NaOH, etc.

September 18, 2010  

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